Given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A
<h3>What is Ohm's Law?</h3>
Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.
It is expressed as;
V = IR
Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.
Given that;
Initially, A circuit has a current I = 1.2A
V = IR
R = V/I
R = V/1.2A ...... let this be equation 1
Next, voltage decreases to one-third of its original amount while the resistance remains constant.
Meaning Voltage = 1/3 of V = V/3
Hence;
V = IR
V/3 = IR
From equation 1 ( R = V/1.2A )
V/3 = I × V/1.2A
V/3 = IV/1.2A
We cross multiply
V1.2A = 3IV
I = V1.2A / 3V
I = 1.2A / 3
I = 0.4A
Therefore, given that the resistance remains constant, if the voltage decreases to one-third of its original amount, the resulting current in the circuit is 0.4A
Learn more about potential difference here: brainly.com/question/2364325
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