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pychu [463]
1 year ago
5

What's the equation

sqrt{1215} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Dima020 [189]1 year ago
6 0

We have the expression

3\sqrt[]{1215}

The square root of 1215 is

\sqrt[]{1215}=34.85685

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Square root of negative 72
Zina [86]

Answer:

i6\sqrt{2} ,  i

( the comma means there is space between the sqrt of 2 and the i.

<em>Hope this helped and plz mark as brainliest!</em>

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<em>Luna G.</em>

3 0
4 years ago
14 over 70 in simplest form
Luda [366]
14/70 in it's simplest form is 1/5

hope this helps :)
5 0
3 years ago
Read 2 more answers
Need help with this question
Lilit [14]

Answer: 30

Step-by-step explanation: To solve this problem, we're going to have to use the Pythagorean theorem...

a² + b² = c²

24² + 18² = c²

576 + 324 = c²

c² = 900

\sqrt{900}

30

30 = c

I hope this helps!

6 0
3 years ago
What is the equation for the line of symmetry in this figure?
Dvinal [7]

Answer:

x = -1

Step-by-step explanation:

By graphing x = -1, you will see that the line splits this rhombus in two equal halves

6 0
4 years ago
Find the general indefinite integral. (use c for the constant of integration. )
Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

7 0
2 years ago
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