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Anon25 [30]
1 year ago
15

Solve by factoring 6p^2 =21p-6

Mathematics
1 answer:
uysha [10]1 year ago
7 0

Given,

The expression is:

6p^2=21p-6

By using the middle term splitting method,

\begin{gathered} 6p^2-21p+6=0 \\ 2p^2-7p+2=0 \\ (x-(\frac{7+\sqrt{33}}{4}))(x+\frac{7+33}{4})=0 \end{gathered}

Hence, the factor is (x-(7+sqrt(33)/4)) (x+(7+sqrt(33)/4)).

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The order in which gifts are received doesn't matter - if child X gets toy 1 then toy 2, it's the same as giving child X toy 2 then toy 1 - so we are counting combinations.

The eldest child receives 3 of the 7 gifts, so they have

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possible choices of gifts.

The next child receives 2 of the remaining 4 gifts, so they have

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The last child receives the remaining 2 gifts, and there is only

\dbinom22 = \dfrac{2!}{2!(2-2)!} = 1

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By the multiplication using, the total number of ways of distributing 7 gifts among 3 children in the prescribed way is 35 • 6 • 1 = 210.

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