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zhenek [66]
1 year ago
8

You started this year with $458 saved and

Mathematics
2 answers:
vovangra [49]1 year ago
6 0

Answer:

s = 14m + 458

Step-by-step explanation:

current amount = 458

14 per month

s = 14m + 458

Alex787 [66]1 year ago
6 0
The equation has to be put into a Y=mx+b format. Basically warp this equation to fit your needs. Make the Y (y intercept) equal S. m (slope) equal $14. x (x coordinate value) equal months or m. Then the b equal $458.

So essentially it will be S=$14m+$458.

It’s this because S is the total value you’re trying to get (the savings)

$14 is linear meaning it’s the same every time or in this case every month so it goes there since the amount also depends on the amount of months. Which is also why m (months) is being multiplied by $14. $458 goes there because it’s the starting value so it will be accounted for every time you calculate with this equation.

I apologize if anything is incorrect or unclear and if you have any questions please ask.
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$2,750

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How many units long is a segment whose endpoints are (2,3) and (7,15)?
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Answer:

13 units

Step-by-step explanation:

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Simply plug in your variables

d = \sqrt{(7-2)^2 + (15-3)^2}

d = \sqrt{5^2 + 12^2}

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Craig saved $10,950 in a year. He saved $75 more than what he saved the previous
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7 0
3 years ago
Read 2 more answers
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Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
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