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Pachacha [2.7K]
1 year ago
10

A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn

a and anchored to the ground at two anchor points on opposite sides of the antenna. The shorter wire makes an angle of 65° with the ground. How far apart are the anchor points? (Round your answer to the nearest foot.)
Mathematics
1 answer:
Dafna1 [17]1 year ago
4 0

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

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nignag [31]
Here you go I think lol

5 0
3 years ago
I am confused. what is 5r– 7 = 2r+ 14
Vlada [557]

Answer:

r=7

Step-by-step explanation:

5r-7=2r+14

add sevento both sides

5r=2r+21

Subtract 2r from both sides.

3r=21

divide both sides by 3

r=7

5 0
3 years ago
12h = 132<br> h=<br><br> i need to know how to do that ^
Wittaler [7]

Answer:

h=11

Step-by-step explanation:

divide:

132/12h

11h

8 0
3 years ago
Read 2 more answers
Whatis the value of y?​
Romashka [77]
Answer is A, y = 65

The top angle is 50 because 180 - 130 = 50
Since the top angle is 50, the two bottom angles have to add up to 130. Since the bottom angles are the same, you can do 130 / 2 to find the angles which equals 65.
3 0
3 years ago
Read 2 more answers
What is the 24th term if the arithmetic sequence where a1 = 8 and a9 = 56
AnnyKZ [126]

Answer:

a_{24} = 146

Step-by-step explanation:

a1 = 8

a9 = 56

Using formula for finding nth term of arithmeric sequence

a_{n} =a_{1} + (n-1)d

We have to find 24th term, therefore n = 24

a_{1} is the first term but we are missing d

d is the difference between the two consecutive terms, lets calculate it first


a9 = 56

Using the above given formula for finding d

put n = 9,  a9= 56

a_{9} =a_{1}+ (9-1)d

56 = 8 + 8d

8d = 48

d = 6


Getting back to main part of finding 24th term

n = 24, d = 6, a1 = 8

put values in nth term formula

a_{n} =a_{1}+ (n-1)d

a_{24} = 8 + (24-1)6

a_{24} = 8 + 138

a_{24} = 146



5 0
3 years ago
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