Check the picture below.

$\bf V=3354~in^3\qquad \qquad 3354=6(w-12)(w+18)
\\\\\\
\cfrac{3354}{6}=w^2+6w-216\implies 559=w^2+6w-216
\\\\\\
0=w^2+6w-775\implies 0=(w+31)(w-25)\implies w=
\begin{cases}
-31\\
\boxed{25}
\end{cases}$

since the width is just a dimension unit, it can't be -31.

what is the length? well, the length is w + 30.

6 0

3 years ago

Which function is graphed below?? TIMED HELP

nadezda [96]

That's the cosine x. The cosine of 0 is 1, so that's how you can tell. The sin of 0 is 0, so that's where the sin graph goes through the y axis

6 0

3 years ago

Say whether the lines AB and CD are parallel in the following diagrams, with reasons ​

Say whether the lines AB and CD are parallel in the following diagrams, with reasons