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-Dominant- [34]
3 years ago
5

If f(x)= 3/x+2-sqrt x-3, complete the following statement:

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

all real numbers greater than or equal to 3

Step-by-step explanation:

There's some ambiguity in your "3/x+2-sqrt x-3."  I will assume that you meant:

   3

---------- - sqrt(x - 3).       Using parentheses often changes everything.

 x + 2  

Here we see that x cannot = -2, because x + 2 would be zero then.  And x must be greater than or equal to 3, so that the input to the sqrt function will be 0 or greater.  The domain for f(x) is all real numbers greater than or equal to 3.  The prohibition against x = -2 has no bearing on the overall domain of this function.

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Since -1/2 is the greatest common factor of the two terms,

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Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

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And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

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at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.




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4 years ago
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Answer:

but where is the polygon....?????

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3 years ago
find the measure of the angle marked with a? Using the inverse trig functions. Round your answer to the nearest degree.​
Colt1911 [192]

Answer:   52°

<u>Step-by-step explanation:</u>

\sin \theta=\dfrac{\text{side OPPOSITE of angle}}{\text{HYPOTENUSE}}\\\\\\\sin \theta =\dfrac{23}{29}\\\\\\.\quad \theta=\sin ^{-1}\bigg(\dfrac{23}{29}\bigg)\\\\\\.\quad \theta =52.47^o

Rounded to the nearest degree: Ф = 52°

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3 years ago
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