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2 years ago

Determine the slope (m) and y-intercept (b) of the line:y = 2x - 3A) m = 3, b = 2B) m = 2, b = -3C) m = -3, b = 2D) m = 2, b = 3

Mathematics

1 answer:

bearhunter [10]2 years ago

6 0

slope of line(m) = 2 and intercept on y axis is -2 that is 2 unit in negative y axis.

Equation of line in slope intercept form:

Slope:

Slope is known as tangent of an angle made by positive X-axis.

We know equation of line in slope and intercept form is,

y = mx + b

where,

m is slope of line

b is intercept on y axis

hence for the given equation,

y =2x - 3

slope (m) will be = 2

intercept on y axis (b) = -3

thus,

option (B) will be correct.

To learn more about slope visit:brainly.com/question/3605446

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What is an equation of the line that passes through (2,2) and is parellel to the line y=7x

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Answer:

Therefore, equation of the line that passes through (2,2) and is parellel to the line $y=7x$ is $y=7x-12$

Step-by-step explanation:

Given:

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Equation of line passing through ( 2, 2) and is parellel to the line y=7x

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Now the equation of line in slope point form given by

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Therefore, equation of the line that passes through (2,2) and is parellel to the line $y=7x$ is $y=7x-12$

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3 years ago

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3 years ago

What is the perimeter of a basement floor that is 40 feet long and 24 feet wide

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4 years ago

Read 2 more answers

The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year. We are interested in the expected

Dominik [7]

Answer:

The probability that a person is audited more than twice is 0.0037 .

Step-by-step explanation:

We are given that The chance of an IRS audit for a tax return with over $25,000 in income is about 2% per year.

We are interested in the expected number of audits a person with that income has in a 16-year period

Now we are supposed to find the probability that a person is audited more than twice.

So, We will use binomial distribution

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So, $P(x \geq 2)= 1-(P(x=0)+P(x=1)+P(x=2)$

Formula : $^nC_x p^x q^{n-x}$

So, $P(x \geq 2)= 1-(^{16}C_0 {(0.02)}^0 {(0.98)}^{16-0}+^{16}C_1 {(0.02)}^1 {(0.98)}^{16-1}+ ^{16}C_2 {(0.02)}^2 {(0.98)}^{16-2})$ $P(x \geq 2)= 1-(\frac{16!}{0!(16-0)!} {(0.02)}^0 {(0.98)}^{16-0}+\frac{16!}{1!(16-1)!} {(0.02)}^1 {(0.98)}^{16-1}+\frac{16!}{2!(16-2)!} {(0.02)}^2 {(0.98)}^{16-2})$

$P(x \geq 2)= 1-(0.9963)$

$P(x \geq 2)= 0.0037$

Hence the probability that a person is audited more than twice is 0.0037 .

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