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Slav-nsk [51]
1 year ago
11

Write an inequality that represents the situation. Jon can do less than 25 sit-ups on an exercise ball. How many sit-ups might J

on do on the exercise ball?
Mathematics
1 answer:
o-na [289]1 year ago
5 0

The inequality is x<25, when Jon cam do less than 25 sit-ups on an exercise ball.

Given that,

Jon can do less than 25 sit-ups on an exercise ball.

We have to find an inequity to illustrate the circumstance.

Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.

The inequality is

Take the exercise balls as x

x<25

Therefore, the inequality is x<25, when Jon cam do less than 25 sit-ups on an exercise ball.

To learn more about inequality visit: brainly.com/question/28823603

#SPJ9

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Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

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We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

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Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

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