Question

in a survey of 2480 golfers, 15% said they were left-handed. the survey's margin of error was 3%. construct a confidence interval for the proportion of left-handed golfers.

Answer 1

The confidence interval for the proportion of left-handed golfers is of:

(0.12, 0.18).

How to obtain a confidence interval?

A confidence interval is calculated as the sample mean plus/minus the margin of error, hence the bounds of the confidence interval are given as follows:

• Lower bound: sample mean - margin of error.

• Upper bound: sample mean + margin of error.

In the context of this problem, these parameters are given as follows:

• Sample mean: 15% as a percentage, 0.15 as a proportion.

• Margin of error: 3% as a percentage, 0.03 as a proportion.

Hence the lower bound of the confidence interval for the proportion of left-handed golfers is:

0.15 - 0.03 = 0.12.

The upper bound of the confidence interval for the proportion of left-handed golfers is:

0.15 + 0.03 = 0.18.

Then the interval is:

(0.12, 0.18).

More can be learned about confidence intervals at brainly.com/question/25890103

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