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salantis [7]
1 year ago
14

3/4 teaspoon water in each gallon. how much in 5 gallons

Mathematics
1 answer:
Vikentia [17]1 year ago
4 0

We can solve this problem by applying the rule of three:

\begin{gathered} \frac{3}{4}\text{ ------------ 1 gallon} \\ x\text{ ------------ 5 gallons} \end{gathered}

then, x is given by

x=\frac{(\frac{3}{4})(5)}{1}

which gives

\begin{gathered} x=(\frac{3}{4})(5) \\ x=\frac{15}{4} \end{gathered}

that is, Pedro will mix 15/4 teaspoons on 5 gallons.

If we convert this result into a mixed fraction form, we obtain

\frac{15}{4}=3\frac{3}{4}

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Will give brainliest, 15 points!
Helga [31]

Answer:

$35

Step-by-step explanation:

This is actually pretty simple!

All you have to do is plug 5 in place of x and solve.

Y=5(5)+10

Y=25+10

Y=35

She raises $35 if she walks 5 kilometers.

3 0
3 years ago
A dice is rolled 5 times. How many possible outcomes are there?
Sholpan [36]

Answer:

7776 outcomes

Step-by-step explanation:

A dice has six faces. So rolling it five times will lead to 6^5 outcomes or 7776 outcomes.

Hope this helps! :D

6 0
3 years ago
You earn $8.50 per hour at your summer job. Write and solve an inequality that represents the number of hours you need to work i
r-ruslan [8.4K]

Answer:

8.50x \geq 348.50

41 hours

Step-by-step explanation:

x= amount of hours

5 0
3 years ago
Please explain <br>without using tables or a calculator evaluate ​
aniked [119]

Answer:

49.2

9

Step-by-step explanation:

7.46² - 2.54² = (7.46 - 2.54)(7.46 + 2.54)

                     = (4.92)(10)

                     = 49.2

(1 x 4) x 3 = [1² + √(1 x 4)] x 3 = [1 + √4] x 3 = [1 + 2] x 3 = 3 x 3 = 9

4 0
2 years ago
The final exam grade of a mathematics class has a normal distribution with mean of 81 and standard deviation of 6.6. If a random
DochEvi [55]

Answer:

The probability that the average final exam grade of this sample is between 77 and 82

P(77≤ x⁻≤ 82 =  0.8315 or 83%

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given random sample size 'n' = 40

Mean of the normal distribution = 81

Standard deviation of normal distribution = 6.6

Let x₁⁻ = 77

Z_{1} = \frac{x_{1} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{77-81}{\frac{6.6}{\sqrt{40} } }

Z₁ = -3.83

Let x₂⁻ = 77

Z_{2} = \frac{x^{-} _{2} -mean }{\frac{S.D}{\sqrt{n} } } = \frac{82-81}{\frac{6.6}{\sqrt{40} } }

Z₂ = 0.958

<em>The probability that the average final exam grade of this sample is between 77 and 82</em>

P(77≤ x≤ 82) = P( -3.83 ≤x≤0.958)

                    = A( 0.958) + A(3.83)

                   = 0.3315 + 0.4995

                   = 0.8315

<em>The probability that the average final exam grade of this sample is between 77 and 82  = 0.8315 or 83%</em>

4 0
3 years ago
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