Answer:
x = 28 m
y = 14 m
A(max) = 392 m²
Step-by-step explanation:
Rectangular garden A (r ) = x * y
Let´s call x the side of the rectangle to be constructed with a rock wall, then only one x side of the rectangle will be fencing with wire.
the perimeter of the rectangle is p = 2*x + 2*y ( but in this particular case only one side x will be fencing with wire
56 = x + 2*y 56 - 2*y = x
A(r) = ( 56 - 2*y ) * y
A(y ) = 56*y - 2*y²
Tacking derivatives on both sides of the equation we get:
A´(y ) = 56 - 4 * y A´(y) = 0 56 - 4*y = 0 4*y = 56
y = 14 m
and x = 56 - 2*y = 56 - 28 = 28 m
Then dimensions of the garden:
x = 28 m
y = 14 m
A(max) = 392 m²
How do we know that the area we found is a local maximum??
We find the second derivative
A´´(y) = - 4 A´´(y) < 0 then the function A(y) has a local maximum at y = 14 m
Answer:
so much for the first time I was just wondering if you want to be a good member of the
Answer:
x=18, m∠1=140, m∠2=40
Step-by-step explanation:
m∠1 and m∠2 will equal up to 180
7x+14+2x+4=180
Combine like-terms
9x+18=180
Subtract 18 from both sides.
9x=162
Divide both sides by 9
x=18
Then plug in 18 for x in the angle measures
7(18)+14=140
2(18)+4=40
Answer:
The answer is <u>D. quadrilaterals</u>
Step-by-step explanation:
- <u><em>All </em></u><u><em>trapezoids </em></u><u><em>are squares. If a shape is a square, then it is also a rectangle and a rhombus. A</em></u><u><em> trapezoid </em></u><u><em>is a </em></u><u><em>quadrilateral </em></u><u><em>with exactly one set of parallel sides</em></u>
Answer:
a= -1
B
Step-by-step explanation:
My opinion:
the slope m = (y2 - y1) / (x2 - x1)
slope m is -5
y2 is 7
y1 is 2
x2 is -2
x1 is a
so the equation will be
-5 = (7 - 2) / (-2 -a )
10 + 5a = 5
5a = -5
a = -1
Then you can plug the value a = -1 into the equation of the slope m to double check it.