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1 year ago

A straight line has a gradient of 4 and passes through the point (2,9).

Mathematics

1 answer:

JulijaS [17]1 year ago

8 0

The equation of the given line passes through the point (2,9) y = 4x + 1.

<h3>What exactly is the slope of a line?</h3>

The slope of a line indicates its steepness. The slope is determined mathematically as "increase over run" (change in y divided by change in x).

<h3>A line equation is defined as:</h3>

The conventional form of a line equation is ax + by + c = 0. Here, the coefficients are a and b, the variables are x and y, and the constant term is c. It is a one-degree equation with variables x and y. The coordinates of both the point on the line that appears in the coordinate plane are represented by the values of x and y.

<h3>According to the given data:</h3>

m = 4

equation of the line = y = mx + c

substituting the value of m = 4

y = 4x + c

the point (2,9):

putting the points in the line of the equation:

x = 2

y = 9

So,

y = mx + c

9 = 4 * 2 + c

9 = 8 + c

c = 1

The equation of the given line y = 4x + 1.

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Step-by-step explanation:

Multiplicative inverse or reciprocal.

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3 years ago

A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$