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cupoosta [38]
1 year ago
9

Which ordered pairs are solutions to the equation x + 6y = 4A) (4, 0)B) (⅓, 2)C) (0, 4)D) (2, ⅓)

Mathematics
1 answer:
aivan3 [116]1 year ago
4 0

Answer

Options A and D are correct.

The ordered pairs that are solutions to x + 6y = 4 include

(4, 0) and (2, ⅓)

Explanation

We need to find the ordered pair(s) that are solutions to x + 6y = 4

To do this, we need to insert each of the options into the equation to know which one(s) satisfy the equation.

Note that the ordered pairs are written in the form of (x, y)

Option A

(4, 0)

x = 4, y = 0

x + 6y = 4

4 + 6(0) = 4

4 + 0 = 4

4 = 4

This option satisfies the equation and is a solution to the equation given.

Option B

(⅓, 2)

x = ⅓, y = 2

x + 6y = 4

⅓ + 6(2) = 4

⅓ + 12 = 4

12⅓ ≠ 4

This option does not satisfy the equation and is not a solution to the equation given.

Option C

(0, 4)

x = 0, y = 4

x + 6y = 4

0 + 6(4) = 4

0 + 24 = 4

24 ≠ 4

This option does not satisfy the equation and is not a solution to the equation given.

Option D

(2, ⅓)

x = 2, y = ⅓

x + 6y = 4

2 + 6(⅓) = 4

2 + 2 = 4

4 = 4

This option satisfies the equation and is a solution to the equation given.

Hope this Helps!!!

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