Leg 1=22
leg 2=120
hypotenuse=122
formula= b1^2+b2^2=h^2
22^2+120^2=122^2
484+14400=14884
14884=14884
yes, it would form a right triangle
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M± where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12± =12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
1. 2300 divided by 45= 51
2.357 divided by 21= 17
3. 1215 divided by 15= 81
4.360 divided by 24= 15