What are the solutions of the equation x4 + 6x2 + 5 = 0? Use u substitution to solve.
1 answer:
Answer:
x = i and x = i
Step-by-step explanation:
Given
+ 6x² + 5 = 0
Using the substitution u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Convert solutions back into terms of x
x² = - 1 ⇒ x =
= i
x² = - 5 ⇒ x =
= i
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Answer:
6555+9876−98766
=16431−98766
=−82335
So in conclusion its - 82335
Hope I helped -
Sleepy~
Use the distributive property
10-6-4x=0
4-4x=0
Answer:
-x = -2 - 3
Step-by-step explanation:
-x = -2 - 3
-x = -5 then make it positive
x = 5
Answer:
8x^4+9x^3+4x-1
Step-by-step explanation:
(6x^3 – 5x^2 + 3x – 5) + (8x^4 + 3x^3 + 5x^2 + x + 4)
Group like terms
8x^4+6x^3+3x^3-5x^2+5x^2+3x+x-5+4
8x^4+9x^3+4x-1
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