Answer:
5 Days ....thats easy....
Hope this answer is correct ..
Have a nice day ahead
Answer:
30 days
Step-by-step explanation:
The common multiples of 15 and 6 are 30, 60, 90 etc and because it increases by 30 each time we can find out that he will play both football and basketball together in thirty days!
When you divide 287 by 68, when it is not rounded, you will get 4.22058823529... (repeated decimal), but when you round it, you can either get the following: 4.22, 4.2, or 4 (choose which ever you want to pick out of these rounded forms.)
Hope this helped!
Nate
The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
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2x + y = 10
2x + 3y = 22
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