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hichkok12 [17]
1 year ago
14

The lengths of two sides of a triangle are 7.8 cm and 5.6 cm. Between what two measures should the length of the third side fall

?
Mathematics
1 answer:
zloy xaker [14]1 year ago
8 0

Hello! To draw a triangle, first, we have to follow a condition of existence.

This rule is:

• one of the sides must be ,bigger, ,than the absolute value, of the ,difference between the other two, sides

• the unknown side must be ,smaller ,than the ,sum of the other, two sides.

Let's write these rules using a, b, and c for the sides:

Considering a = 7.8 and b = 5.6:

[tex]\begin{gathered} |a-b|So, the third side must be smaller than 13.4 and bigger than 2.2.

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<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units</h2>

Step-by-step explanation:

Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

x_1=2,y_1=1,x_2=12,y_2=2,x_3=12 and      y_3=8

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                          = \sqrt{(2-12)^{2} +(1-8)^2}

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Let the perpendicular distance from B to AC be = x

According To Problem

\frac{1}{2} \times  x \times \sqrt{149} = 54

⇔x =\frac{108}{\sqrt{149} } units

Therefore the perpendicular distance from B to AC is = \frac{108}{\sqrt{149} } units

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