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1 year ago

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The expression 16t² models the distance in feet that an object falls during the first t seconds after being dropped. What is the

distance the object falls during each time?
0.5 second

1 answer:

lbvjy [14]1 year ago

5 0

If the expression 16t² models the distance in feet that an object falls during the first t seconds after being dropped, then the distance of the object during 0.5 second is 4 feet

Given,

The expression model of the distance in feet that an object falls during the first t second after being dropped = $16t^{2}$

Time = 0.5 second

Then the distance = $16(0.5)^{2}$

=16×0.25

=4 feet

Hence, if the expression 16t² models the distance in feet that an object falls during the first t seconds after being dropped, then the distance of the object during 0.5 second is 4 feet.

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