Question

In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=7 and BC=6, what is the area of the shaded region
answer: height=62=3
Now we can find the area of one of the shaded triangles:
AAA=12⋅b⋅h=12⋅7⋅3=10.5
Now that we know the area of one triangle, we can multiply by two to get the total area of the shaded region.
10.5⋅2=21
So the area of the shaded region is 21.

Answer 1

The area of the shaded region is a 21 units.

According to the statement

We have to find that the area of the shaded region.

So, For this purpose, we know that the

A rectangle is a quadrilateral in which all the angles are equal and the opposite sides are equal and parallel.

From the given information:

In rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=7 and BC=6.

Then

see the attached figure to better understand the problem

Remember that the area of triangle is equal to

Area =  1/2*Base*Height

Then

Base = 7 units

Height = 6/2 = 3 units

Then

Find the area of triangle ABE

Area =  1/2*Base*Height

Area =  1/2*7*3

Area =  1/2*21

Area =  10.5.

Then

Find the area of triangle CDE

Area =  1/2*Base*Height

Area =  1/2*7*3

Area =  1/2*21

Area =  10.5.

Find the area of the shaded region

Area =  2*10.5.

Area = 21

So, The area of the shaded region is a 21 units.

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