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Katena32 [7]
8 months ago
15

Given the equation y=2x+3, write a second equation that would create an independent consistent linear system

Mathematics
1 answer:
STALIN [3.7K]8 months ago
3 0

Two equations will be called independent if their graphs touch only on one point (they have one solution for the x-value and one solution for the y-value), and two equations will be dependent if they touch at every point (there is an infinite number of solutions).

This definition of independent and dependent equations is shown in the following diagram. Consider that there are two lines, one red line and one blue line:

They are independent if they touch only on one point and dependent if they touch at every point (they are the same line).

In our case, we are asked to write an equation in order to create an independent consistent linear system.

Note: Consistent means that the system has a solution.

First, we graph the given equation:

y=2x+3

There are many different equations that will form an independent consistent linear system with this equation.

We are going to choose the following line equation:

y=-x+1

Because when we graph this equation next to the previous line:

We can see that they touch at one point, thus there is a solution and the system is independent --> we have created an independent consistent linear system.

Answer:

y=-x+1

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What is the value of the function at x=−2?
Nezavi [6.7K]

Answer:

I would think y equals 2

Step-by-step explanation:

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2 years ago
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Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one
dalvyx [7]

Answer with Step-by-step explanation:

We are given that

f(x)=\frac{3x-1}{x}

For each real number x\neq 0

To prove that f is one -to-one.

Proof:Let x_1 and x_2 be any nonzero real numbers such that

f(x_1)=f(x_2)

By using the definition of f to rewrite the left hand side of this equation

f(x_1)=\frac{3x_1-1}{x_1}

Then, by using the definition of f to rewrite the right hand side of this equation  of f(x_1)=f(x_2)

f(x_2)=\frac{3x_2-1}{x_2}

Equating the expression then we get

\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}

3x_1x_2-x_2=3x_2x_1-x_1

3x_1x_2-3x_1x_2+x_1=x_2

x_1=x_2

Therefore, f is one-to-one.

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2 years ago
If Angela has $500 to invest at 2.5% per annum compounded quarterly, how long will it be
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N = number of compounding periods
Years = log (total / principal) / n * log (1 + rate / n)
Years = log (750 / 500) / 4 * log (1 + .025/n)
Years = log (1.5) / 4 * log (1<span><span>.00625) </span>
</span> <span>Years = 0.17609125906 / 4 * 0.0027058933759
</span><span>Years = 0.17609125906 </span> / <span> <span> <span> 0.0108235735 </span> </span> </span>
Years = <span> <span> <span> 16.2692348382 </span> </span> </span>

Source Calculator
http://www.1728.org/compint.htm


5 0
2 years ago
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