Question

I’m having trouble solving this I would like some assistance

Answer 1

Part A:

Finding the probability of P(Z < -1.27), we refer to the z-table to the left of the distribution and we have

Therefore

$P(Z$

Part B:

Doing the same process as above, however we also need to find the P(Z < 1.68)

Solving for P(-1.27 < Z < 1.68) we have

$\begin{gathered} P\mleft(-1.27Part C:Again we need to find first P(Z < 1.96) to the left of zSince this probability is of P(Z < 1.96) , solve for P(Z > 1.96) by[tex]\begin{gathered} P\mleft(Z>1.96\mright)=1-P\mleft(Z1.96)=1-0.97500 \\ \\ \text{Therefore,} \\ P(Z>1.96)=0.02500 \end{gathered}$