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LekaFEV [45]
1 year ago
12

Yes I am having problems learning about equations

Mathematics
1 answer:
alisha [4.7K]1 year ago
5 0

If we have a function [Equation] it would look something like this:

3x+y=4

In order to solve for both values and graph it [If that's what you are trying to do], you solve for y and then replace values [Of your own choosing, or they are given to be studyed] in x, after we replace the values in x, we are going to have the respective value of y.

From our previous example, it would be:

y = -3x+4

So, when we start replacing the values of X, we will get the respective values for Y, let's try doing it from -3 to 3.

x = -3 => y = -3(-3)+4 => y = 13

x = -2 => y = -3(-2)+4 => y = 10

x = -1 => y = -3(-1)+4 ) => y = 7

x = 0 => y = -3(0)+4 => y = 4

x = 1 => y = -3(1)+4 => y = 1

x = 2 => y = -3(2)+4 => y = -2

x = 2 => y = -3(3)+4 => y = -5

From this, we would end up with the following points:

(-3, 13)

(-2, 10)

(-1, 7)

(0, 4)

(1, 1)

(2,

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Answer:

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The difference of the given expression is

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Step-by-step explanation:

Given expression is \frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})

To find the difference of the given expression as below :

\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})

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Therefore \frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}

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Therefore option \frac{(x+5)(x+2)}{x^3-9x} is correct

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