Question

Use the figure shown. Let point D be at (-4,1) . Use the sides of triangle BDA to find the slope of the line.

Answer 1

The slope of the line shown in the figure having equation x + 2y = 0 is 1/2.

The point A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and Point C is at ( -2 , 2 ).

Let point D be at ( -4 , 1 ).

Now the new triangle is ΔBDA and the corner points are A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and  point D is at ( -4 , 1 ).

The equation of line passing through two points  is given by:

$(y-y_{1} ) = (\frac{y_{2}-y_{1} }{x_{2} - x_{1} })(x - x_{1} )$

The equation of line passing through two points A( -2 , 1 ) and B( -4 , 2 ) IS

y - 1 = ((2-1)/(-4-(-2)))  (x-(-2))

y - 1 = (1/(-2)) (x+2)

2y -2 = -x -2

x + 2y = 0

The equation of straight line is x + 2y = 0

The equation in slope intercept form can be written as,

y = x/2 + 0

Slope = m = 1/2

Intercept = c = 0

So, we can conclude that 1/2 is the slope of the line .

To know more about Slope - intercept form refer to link:

brainly.com/question/1884491

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