Enter the ordered pair for the vertices for (Ry-axis o T(2,0))(QRST).

1 answer:

7 0

On solving the provided question, we got to know the vertices those are - Q' = (-3, 3), R' = (-5, -3), S' = (-2, -2), T' = (0, 1)

<h3>what is vertices?</h3>

As kids learn about the characteristics of 3D forms, vertices, faces, and edges start to appear often in geometry. Here's what it means and how to figure out how many vertices, faces, and edges each form has. The most popular forms' edge, face, and vertex counts are also included.

$The coordinates of the vertices of the quadrilateral are;$

$T(-2, 1), Q(1, 3), S(0, -2), R(3, -3)$

The coordinates of the vertices of the quadrilateral are;

$T(2, 0)QRST, gives;\\ T(2, 0)QRST→ T(-2 + 2, 1), Q(1 + 2, 3), S(0 + 2, -2), R(3 + 2, -3)\\ T(2, 0)QRST→ T(0, 1), Q(3, 3), S(2, -2), R(5, -3)\\$

For the next process R y-axis which is the reflection about the y-axis, the preimage (x, y) becomes the image (-x, y)

Therefore, we have;

$R y-axis(T(0, 1), Q(3, 3), S(2, -2), R(5, -3)) = T'(0, 1), Q'(-3, 3), S'(-2, -2), R'(-5, -3)\\ From which we get (Ry-axis T(2, 0))(QRST = T'(0, 1), Q'(-3, 3), S'(-2, -2), R'(-5, -3).$