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FromTheMoon [43]
1 year ago
6

if a, b, and c are prime numbers, do (a b) and c have a common factor that is greater than 1? (1) a, b, and c are all different

prime numbers. (2) c ≠ 2\
Mathematics
1 answer:
klio [65]1 year ago
8 0

If a,b, and c are prime numbers, do (a*b) and c have a common factor that is greater than 1

(1) a,b, and c are all different prime numbers

(2) c≠2

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a b = 1*3 = 3

3 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a *b = 1*3 = 3

3 and 2 does not have a common factor aside 1

2. c \neq 2

Let's assume values of 2,7 and 3 to a b and c response

a * b = 2 *7 = 14

14 and 3 does not have a common factor aside 1

learn more about of prime number here

brainly.com/question/14410795

#SPJ4

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2 years ago
A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec
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Answer:

A. The solutions are x=3i,\:x=-3i.

B. The factored form of the quadratic expression x^2+9=(x-3i)(x+3i)

Step-by-step explanation:

A. To find the solutions to the quadratic equation x^2+9=0 you must:

\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}

x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i

The solutions are:

x=3i,\:x=-3i

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor x^2+9:

First, multiply the constant in the polynomial by i^2 where i^2 is equal to -1.

x^2+9i^2

Since both terms are perfect squares, factor using the difference of squares formula

a^2-i^2=(a+i)(a-i)

x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)

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