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kumpel [21]
1 year ago
7

15. There were 59,500 people who attended a

Mathematics
2 answers:
MariettaO [177]1 year ago
7 0

Answer:

10,710 People claimed their water bottle

Step-by-step explanation:

Mumz [18]1 year ago
7 0
ANSWER: 13,423 people.

EXPLANATION: 24% of 59,500 is 14,280 people. 6% of those 14,280 people did NOT claim their water, so that means 94% of them did. 94% of 14,280 is 13,423 people.
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choose the single logarithm expression that is equivalent to the one shown 1 / 3 log 3x + 2 / 3 log 3x​
alexgriva [62]

Answer:

\log (3x)

Step-by-step explanation:

The given logarithmic expression is:

\frac{1}{3}\log(3x)+ \frac{2}{3}\log(3x)

This is the same as:

\frac{1}{3}\log(3x)+ \frac{1}{3}\log(3x)^2

\frac{1}{3}(\log(3x)+ \log(3x)^2)

We now apply the product rule to get:

\frac{1}{3}\log(3x)\times (3x)^2

\frac{1}{3}\log (3x)^3

We now apply the power rule to get;

\frac{3}{3}\log (3x)=\log (3x)

6 0
3 years ago
In △JKL, if m∠J = 90° then∠K and∠L are
netineya [11]

Answer:

acute

Step-by-step explanation:

since a full triangle is 180, angles K and L must be 90 when put TOGETHER so each one would have to be less than 90 :)

7 0
3 years ago
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A dealership purchased a four-door sedan for $17,000 and then sold it at 15% markup. the dealership paid the buyer $4000 for a t
disa [49]
Hi there
17,000×0.15
=2,550
4,000×0.25
=1,000

Profit=2550+1000=3550

Hope it helps
4 0
3 years ago
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An oval track is made by erecting semicircles on each end of a 44 m by 88 m rectangle. Find the length of the track and the area
Dmitry_Shevchenko [17]

Answer:

The length of the track is 247 m.

The area enclosed by the track is  5391 . 76 sq m.

Step-by-step explanation:

The length of the rectangle  = 88 m

The width of the rectangle  =  44 m

Now, as we know the semicircles are at the end of rectangular track.

So, the diameter of semicircles = Width of the rectangle

⇒ The diameter of the semi circle  = 44 m

⇒Radius of the semi circle  = 44/2 = 22 m

TOTAL LENGTH OF TRACK  

= 2 ( Length of rectangle)  + 2 (Circumference of 1 semicircle)

= 2 x (88 m)  + 2 (\frac{2\pi r}{2})

= 176 m + 2 (3.14)(22 m)  = 176 + 71.08 =  247 m

Hence, the length of the track is 247 m

TOTAL AREA OF TRACK  

= (Area of rectangle)  + 2 (Area of 1 semicircle)

= (Length x Width)  +    2 (\frac{\pi r^2}{2})

=  (44  m x 88 m) +  (3.14)(22 m)(22 m)   = (3872  + 1519.76) sq m

=  5391 . 76 sq m

Hence, the area enclosed by the track is  5391 . 76 sq m.

7 0
3 years ago
What is 8 x 6 x 1/2?
Lena [83]

Answer:

24

Step-by-step explanation:

8 x 6 = 48 and 48/2 = 24

4 0
3 years ago
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