Answer:
x = -2/5
y = 12/5
Step-by-step explanation:
Substitution method;
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
x = 2 - y
substitute the value of x in equ (i)
(-2)* (2-y) + 3y = 8
-4 + 2y + 3y = 8
5y = 8 + 4
y = 12/5
substitute the value of y in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
elimination method:
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
(i) ====> -2x + 3y = 8
multiply equ (ii) by 2 ====> <u> 2x + 2y = 4</u>
add (i) and (ii) 5y = 12
y = 12/5
Substitute in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
Answer:
Step-by-step explanation:
5/14=x/28
Cross multiply to get
14x=140
Divide both sides by 14
x=10
Or
See that 28 is 14*2 and multiply 5*2 to get the same answer
Answer:
t = 0.99
Step-by-step explanation:
1.2t - 1.44= 0.25t
first, we add 1.44 to both sides to move it
1.2t - 1.44 = 0.25t
+1.44 +1.44
______________
1.2t = 0.25t + 1.44
second, we want to solve for t, so we must get the variable alone (add 0.25t to 1.2t)
1.2t = 0.25t + 1.44
+0.25t +0.25t
1.45t = 1.44
third, to get t alone we must divide by 1.45 on both sides
1.45t = 1.44
t = 0.9931034483
rounded this would be 0.99
Answer:
ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.
That is, S = D/t
Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have
S1 = D1/t
We can then say he ran a distance
D1 = t × S1
= 3600S1
Similarly, let's say Karleigh ran a distance
D2 = t × S2
= 3600S2
Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.
Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10
D1 = 3600 × 5
= 18000
D2 = 3600 × 10
= 36000
This makes D2 bigger than D1. this is an example i found on the internet.
Step-by-
hope this helps, good luck
The answer is = because they are all equivalent to 1/4.