Answer:
x² + 6x - 27 = 0
x² + 9x - 3x - 27 = 0
x ( x + 9 ) - 3 ( x + 9 ) = 0
( x + 9 ) ( x - 3 ) = 0
Thus ,
x = -9 or x = 3
I hope it helps you
#Indian : )
Equation of circle
(x-h)^2 + (y-k)^2 = r^2
=> (x-10)^2 + (y+4)^2 = 4 is the answer
It looks like it goes through (0,-3) and (1,2), so the gradient is (change in y)/(change in x) ->
(-3-2)/(0-1) = 5
So y=5x+b
Then as we know it passes the y axis at (0,-3) so b= -3
So we have y=5x-3
My guess would be A ! Hope this helps
