N³- n² + 3n - 3 = (n²+3 )(x-1 )
Answer:
16. Adults = $12
17. 750 ml
18. $9
19. 96 students
20. 5/6x
Step-by-step explanation:
16.
A child pays = $9
Bus fee = 1/3 of $9
= 1/3× 9
= $3
Admission fee for a child= amount paid - bus fee
= $9 - $3
= $6
What was the admission fee for adults, if children get in for haprice
Children = 1/2 of adults
$6 = 1/2 × adults
Adults = 6÷ 1/2
= $12
Adults = $12
17.
Leaking rate = 10 ml per minutes
One and quarter of an hour
1 hour = 60 minutes
Quarter of an hour = 15 minutes
Total time = 75 minutes
Air lost in 75 minutes = 10 ml × 75
= 750 ml
18. 4 glasses for $3
1 dozen of glasses = 12
12 glasses = $x
4 = 3
12 = x
Cross product
4*x = 3*12
4x = 36
x = 36 / 4
= 9
x = $9
19.
Total students = x
1/2x = soccer
Rugby = 1/2 of 1/2x
= 1/2 * 1/2x
= 1/4x
24 = 1/4x
x = 24÷1/4
= 24 × 4/1
x = 96 students
20.
Total petrol = x
Petrol in the tank = 1/2x
Petrol used = 1/3 of 1/2x
= 1/3 × 1/2x
= 1/6x
Petrol remaining after the trip = x - 1/6x
= 6x-x/6
= 5/6x
Answer:
this link will help
Step-by-step explanation:
Answer:
D. The same point
Step-by-step explanation:
An equilateral triangle can be defined as a type of triangle that has all of its sides being equal in length.
This ultimately implies that, an equilateral triangle comprises of three (3) congruent sides and as such creates three (3) congruent angles that measures 60° each. Also, the sum of the congruent angles of an equilateral is always equal to 180°.
Hence, in an equilateral triangle, the incenter, orthocenter, circumcenter, and centroid are the same point i.e all of the three (3) centers fall on the same point or spot.
Answer:
x = 10/3
Step-by-step explanation:
The question is incomplete without the diagram as this would enable us solve for x. Find attached the diagram used for solving the question.
We can tell from the question we are to compare two triangles drawn together (smaller one drawn in a bigger one) using similar triangles.
Using similar triangles to solve for x,
∆ABC = ∆ADE
∠CBA = ∠EDA = 90°
Let's relate the ratio of their corresponding sides.
(Adjacent/opposite) in ∆ABC
= (Adjacent/opposite) in ∆ADE
AB/CB = AD/ED
AB = 6
CB = 2
AD = AB + BD = 4+6 = 10
ED = x
6/2 = 10/x
3 = 10/x
3x = 10
x = 10/3