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qwelly [4]
1 year ago
13

Reduce the rational expression to lowest terms. If it is already in lowest terms, enter the expression in the answerbox. Also, s

pecify any restrictions on the variable.a²-3a-4/a² + 5a + 4Rational expression in lowest terms:Variable restrictions for the original expression: a

Mathematics
1 answer:
givi [52]1 year ago
7 0

Factorize both quadratic polynomials, as shown below

\begin{gathered} a^2-3a-4=0 \\ \Rightarrow a=\frac{3\pm\sqrt{9+16}}{2}=\frac{3\pm\sqrt{25}}{2}=\frac{3\pm5}{2}\Rightarrow a=-1,4 \\ \Rightarrow a^2-3a-4=(a+1)(a-4) \\  \end{gathered}

Similarly,

\begin{gathered} a^2+5a+4=0 \\ \Rightarrow a=\frac{-5\pm\sqrt{25-16}}{2}=\frac{-5\pm3}{2}\Rightarrow a=-1,-4 \\ \Rightarrow a^2+5a+4=(a+1)(a+4) \end{gathered}

Thus,

\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{(a+1)(a-4)}{(a+1)(a+4)}

Therefore, since the denominator cannot be equal to zero.

<h2>The variable restrictions for the original expression are a≠-1,-4</h2>

Then, provided that a is different than -1,

\Rightarrow\frac{a^2-3a-4}{a^2+5a+4}=\frac{x-4}{x+4}<h2>The rational expression in the lowest terms is (x-4)/(x+4)</h2>

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