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ivolga24 [154]
1 year ago
5

A bowl holds Fraction 3 over 10 cups of oil when it is Fraction 2 over 5 full. Which statement best describes the quotient of 3

over 10 division sign2 over 5?
1. The maximum amount of oil the bowl can hold is Fraction 3 over 4 cup.
2. The amount of oil that can be still poured in the bowl is Fraction 3 over 4 cup.
Mathematics
1 answer:
Allisa [31]1 year ago
6 0

The statement that describes the quotient of 3 over 10 division sign2 over 5 is A. The maximum amount of oil the bowl can hold is Fraction 3 over 4 cup.

<h3>How to illustrate the fraction?</h3>

From the information given, we are told that a bowl holds fraction 3 over 10 cups of oil when it is Fraction 2 over 5 full.

Therefore, the statement that best describes the quotient of 3 over 10 division sign2 over 5 will be that the maximum amount of oil the bowl can hold is fraction 3 over 4 cup.

In conclusion, the correct option is A.

Learn more about fractions on:

brainly.com/question/78672

#SPJ1

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taurus [48]
The answer is A. 34

r=34

r/6 = 5 2/3

5x3+2 over 3 = 17/3

r= 17/3 x 6 = 102/3

102 ÷ 3 = 34
3 0
3 years ago
Both and tell why pls……..
RoseWind [281]

Answer:

4) A

5) E

Step-by-step explanation:

#4

\frac{x}{y}=\frac{1}{10} * \frac{z}{y}

\frac{x}{y} =\frac{1z}{10y}

Cross multiply the equation and you get:

10xy=zy

Since \frac{a}{b}=\frac{c}{d}  is the same thing as ad=bc, you can change the equation into \frac{x}{z} =\frac{y}{10y}

Cancel out the y on the top and bottom and you get 1/10

#5

\frac{2}{3} *\frac{x}{2} =5, simplify and you get \frac{x}{3} =5 so x=15

\frac{1}{5} * 3(x) is equal to \frac{1}{5} *3(15) after you plug in x, and that is equal to 9

7 0
3 years ago
The design for a patio consists of a square with a semicircle adjacent to one side of the square. the diameter of the semicircle
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7 0
4 years ago
What is 12/5 turned into a mixed number
poizon [28]

Answer: 2 2/5

Step-by-step explanation:

Denominator stays the same, divide 12 and 5, remainder at the top

3 0
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ELEN [110]

Answer:

If you have the radius:

You can use the Circumference which us equal to:

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Then substitute:

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8 0
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