TQRS is an inscribed quadrilateral.
5 x - 52° + 3 x + 40° = 180°
8 x - 12° = 180°
8 x = 180° + 12°
8 x = 192°
x = 192° : 8 = 24°
m∠ R = 3 · 24° + 40° = 112°
m∠ T = 5 · 24° - 52° = 68°
m∠ S = 360° - ( 68° + 68° + 112° ) = 112°
Answer:
m∠R, m∠S, m∠T = 112°, 112°, 68°.
Answer:
8/3mph
Step-by-step explanation:
you must multiply both fractions by the reciprocal of 3/10 which is 10/3
(4/5 * 10/3) / (3/10 * 10/3)
(40/15) / (30/30)
(8/3) / 1
8/3 /1 = 8/3
Answer:
here look for it there is a sol
Step-by-step explanation:
https://www.careerlauncher.com/cbse-ncert/class-9/Math/CBSE-SurfaceAreasandVolumes-NCERTSolutions.html
By identifying the largest exponent in each expression, we see that the answers are:
a) D = 3.
b) D = 5.
c) D = 0.
<h3>
</h3><h3>
How to determine the degree of an expression?</h3>
The degree is just the largest exponent of the variable in an expression.
First, we have:
a) √3xyz - 5
The largest exponent is on the term √3*xyz is 3 (because we add the 3 exponents 1 of x, y, and z) so this expression has a degree of 3.
b) y² - 3y⁵ -y + 2y³ - 4
Here the largest exponent is on the second term, so we can see that the degree is 5.
c) -10³
Here we don't have a variable, so this is a constant, which means that the degree is zero, because we could write:
-10³*x⁰
Where we use the fact that x⁰ = 1
If you want to learn more about degrees:
brainly.com/question/1600696
#SPJ1
Answer:
X = -2
Step-by-step explanation:
Hope this helps
