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1 year ago

Does the graph represent a function?

Mathematics

1 answer:

lisov135 [29]1 year ago

7 0

It is true that the graph represents a function

<h3>How to determine if the graph represent a function?</h3>

For a graph to represent a function, the following must be true

Each x value on the graph must point to exactly one

The above means that the function must pass the vertical line test

The given graph would pass the vertical line test

This is so because:

Each x value on the graph points to exactly one

Hence, the graph represents a function

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I need help 100 points if you answer this

lawyer [7]

Answer:

I will do a couple of the since there is so many with little time, any more I do is if you do not understand.

Step-by-step explanation:

1st row(column?)- Decimal form= 0.125 Percent= %12.5

2nd- Fraction= 3/4 Decimal= 0.75

3rd- Decimal= 0.6 Percent- %60

Hope this helps :)

6 0

3 years ago

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Help on number 1 is needed!!

tamaranim1 [39]

Answer:

Substitute the values given for f(x) and g(x), in 1. they say f(x)=4x and g(x)=1-x

and basically just substitute them for the functions themselves.

4x+1-x

add like terms!

4x-x = 3x!

3x+1 is your simplified answer, since it is an expression it cannot be simplified any further.

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3 years ago

The molarity of a solute in solution is defined to be the number of moles of solute per liter of solution (1 mole = 6.02 × 1023

KengaRu [80]

Answer:

a) 0.65

b) 0.1581

Step-by-step explanation:

We are given the following in the question:

Distribution of X:

Mean = 0.125

Standard deviation = 0.05

Distribution of Y:

Mean = 0.350

Standard deviation = 0.10

Solution:

$M = X + 1.5Y$

a) mean of M

$\mu_M = \mu_X + 1.5(\mu_Y) = 0.125 + 1.5(0.350) = 0.65$

b) standard deviation of M

If X and Y are independent then,

$Var(X+Y) = Var(X) + Var(Y)\\Var)aX) = a^2Var(X)$

$Var(M) = Var(X+1.5Y)\\Var(M) =Var(X) + (1.5)^2Var(Y)\\Var(M) = (0.05)^2 + (1.5)^2(0.10)^2 = 0.025$

Standard deviation of M =

$=\sqrt{Var(M)} = \sqrt{0.025} = 0.1581$

4 0

3 years ago

Answer plz ASAP, I will give brainliest no links

goblinko [34]

Answer:

A: (10k+m)(10k−m)

Step-by-step explanation:

3 0

3 years ago

Find the coordinates for the midpoint of the segment with endpoints given 12,4 and -8,8

borishaifa [10]

<h2>Hello!</h2>

The answer is:

The coordinates of the midpoint are:

$x-coordinate=2\\y-coordinate=6$

We can find the midpoint of the segment with the given endpoints using the following formula.

The midpoint of a segment is given by:

$MidPoint=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

We are given the points:

$(12,4)\\$

and

$(-8,8)\\$

Where,

$x_{1}=12\\y_{1}=4\\x_{2}=-8\\y_{2}=8$

So, calculating the midpoint, we have:

$MidPoint=(\frac{12+(-8)}{2},\frac{4+8}{2})$

$MidPoint=(\frac{4}{2},\frac{12}{2})$

$MidPoint=(2,6)$

Hence, we have that the coordinates of the midpoint are:

$x-coordinate=2\\y-coordinate=6$

Have a nice day!

8 0

3 years ago

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