Answer: 26 items
Step-by-step explanation:
Let x denotes the last year's output.
Given : A company has determined that it must increase production of a certain line of goods by 112 times last years production.
The new output will be 2885 items.
According to the above statement we have the following equation :-
Divide both sides by 112, we get
Hence, the last year's output =26 items
Answer:
35
Step-by-step explanation:
Put the numbers in the formula and do the arithmetic.
nCk = n!/(k!(n -k)!)
7C3 = 7!/(3!(7-3)!) = 7·6·5/(3·2·1) = 7·5 = 35
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It is convenient to use the largest of the factorials in the denominator to cancel as many factors as you can from the numerator, then cancel factors from the remaining numbers. Here after canceling 4! = 4·3·2·1 from the numerator, we are left with 7·6·5 divided by 3! = 3·2·1 = 6. Obviously, this will cancel the 6 in the numerator product, leaving only 7·5 = 35.
Some graphing and/or scientific calculators will have this function built in.
Using the Empirical Rule, it is found that 229 batteries have lifetimes between 3.0 hours and 3.4 hours.
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By the Empirical Rule, in a normal variable: 68% of the measures are within 1 standard deviation of the mean, 95% are within 2 and 99.7% are within 3.
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3 = 3.2 - 2(0.1)
3.4 = 3.2 + 2(0.1)
229 batteries have lifetimes between 3.0 hours and 3.4 hours.
A similar problem is given at brainly.com/question/24552083