Question

Gold has a density of 19. 3 g/cm^3 and can be rolled into very thin sheets. If a 285 mg sample of gold is rolled into a "circle" of radius 0. 78 cm. Find the thickness of the "circle," in microns.

Answer 1

The thickness of the given circle made of the sample gold is 77.4 microns.

We know, the density of a material is the ratio of the mass of the material to the volume of the material.

Density = mass/volume

Therefore, volume = mass/density

Here, the density of the gold = 19.3 gm/cm³

Mass of the gold is = 285 mg = 0.285 gm

Therefore, the volume of the given gold is

= mass/density

= 0.285/19.3 cm³

= 0.0148 cm³

The circular sheet of gold has a radius of 0.78 cm.

Therefore, the area of the circular sheet is

= πr² cm²

= π(0.78)² cm²

= 1.911 cm²

Therefore, the thickness of the circular sheet is

= volume of the sheet/ area of the sheet

= 0.0148 cm³/ 1.911 cm²

= 7.74 × 10⁻³ cm

= 7.74 × 10⁻⁵ m

= 77.4 × 10⁻⁶ m

= 77.4 microns

Learn more about the volume of a material here: brainly.com/question/9214759

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