Question

Select the correct answer. What is the value of the limit lim x 2 (x^2+3x+1/x^3+x+1) ? A. B. 1 C. D.

Answer 1

So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

How to get the value of the limit?

Here we want to get the limit:

$\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1}$

First, we can try to evaluate directly in x = 2 and see if it does not generate any problem, we will get:

$\lim_{x \to \ 2} \frac{x^2 + 3x + 1}{x^3 + x + 1} = \frac{2^2 + 3*2 + 1}{2^3 + 2 + 1} = 1$

So by direct evaluation we can see that the limit when x tends to 2 is equal to 1.

If you want to learn more about limits:

brainly.com/question/2264127

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