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Hunter-Best [27]
4 years ago
13

8 (40+7) = ( 8. ) + (8 7

Mathematics
1 answer:
prohojiy [21]4 years ago
8 0
The first part is 8 x 40=320
8 x 7=56
320+56 and i am not sure what you have going on on the other half
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3 years ago
Can someone please help me with this. whoever answers first will be the brainleyist
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Answer:

Step-by-step explanation:

6(5+x) = 30 + 6x

1. Distribute the 6 to both the 5 and the x.

7x5x3 = 105

1. Just multiply them together.

28 - 3(2+4)/9 = 26

1. PEMDAS

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4 0
3 years ago
Read 2 more answers
Find the sum of the first 11 terms of the sequence -7,-4,-1, 2 ...
lawyer [7]

Answer:

A    The sum of the first 11 terms is 88

Step-by-step explanation:

Since -4 - (-7) = -1 - (-4) = 2 - (-1) = 3

Your sequence is an arithmetic sequence with a common difference of 3.

The formula for the sum of an arithmetic sequence is

S = \frac{n(a_{1} + a_{n}) }{2}  where a_{1} = the first term, a_{n}  =  the  last  term, n = the  number  of  terms  to  be  added, and S = the  sum

In your case a_{1}  = -7,  n = 11  and a_{n}  =  a_{11}

We know everything except the eleventh term.

So, we need to find the eleventh term or  a_{11} = a_{1} + (n - 1)d

                                                                     =  -7 + (11 - 1)3

                                                                     = -7 + 30 = 23

Now, S = \frac{11(-7 + 23)}{2}  = \frac{11(16)}{2}  = 88

The sum of the first 11 terms is 88

7 0
3 years ago
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