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castortr0y [4]
3 years ago
14

Los condimentos estan en frascos

Spanish
2 answers:
Svetlanka [38]3 years ago
6 0

Answer:

The condiments are in jars

GuDViN [60]3 years ago
4 0

Answer:

"Los condimentos estan en frascos"

"the seasonings are in jars"

since heres no "el" which means "the" is just "jars" not "the jars" cuz that wold be "el frascos"

and estan is plural because of " los condimentos"

~batmans wife dun dun dun....

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motikmotik

Answer:

Explanation:

estos últimos días he estado de vacaciones en ecuador,la verdad es un sitio muy bonito y tranquilo para un viaje familiar,estuvimos en muchos sitios pero el mejor sin duda fué la casa de mis primos José Fernando y María Luisa,los cuales siempre son muy amables conmigo,estuve con ellos durante los últimos días y me hicieron sentir como en casa.

Ahora la verdad es que echo de menos todos los recuerdos que he traído conmigo,pero los recordaré siempre.

if i gotta be honest i didnt read everything you wrote but this is a text talking bout a trip to ecuador bringing up how u felt on the last days and w correct spelling,xoxo

if u r thanful follow me on ig uxiarial_

7 0
2 years ago
What does la estación mean?
LenKa [72]
I think it means the station
4 0
4 years ago
Read 2 more answers
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Cerrena [4.2K]

Answer:

I can't understand what you are saying

Explanation:

6 0
3 years ago
Which 2 letters in the Spanish alphabet sound the same?​
Airida [17]
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3 0
3 years ago
Simplify x^3-125/2x-10
MAVERICK [17]
We \ first, \ simplify \  \frac{125}{2} \\ \\   \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\  pulling \ out \ like \ factors : \\ \\  2x^3 - 125x  =   x * (2x^2 - 125) \\ \\ Factoring: \  2x^2 - 125

<span>Here's how!</span>

Proof :  \ (A+B) * (A-B) =\\&#10;         A2 - AB + BA - B2 =\\&#10;         A2 - AB + AB - B2 = \\&#10;         A2 - B2\\

<span>Therefore</span> . . . 

\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }

<span>The factors would then be the following:</span>

→ ( Leading \  Coefficient :  1,2)
→ (Trailing Constant) :  1 ,2 ,4 ,5 ,10 ,20

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }} <span>✔</span>
6 0
4 years ago
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