Answer:
Tap A 3hrs
Tap B 6hrs
Step-by-step explanation:
Let the volume of the swimming pool be Xm^3.
Now, to get the appropriate volume, we know we need to multiply the rate by the time. Let the rate of the taps be R1 and R2 respectively, while the time taken to fill the swimming pool be Ta and Tb respectively.
x/Ta= Ra
x/Tb= Rb
X/(Ra + Rb)= 2
Ta = Tb - 3
From equation 2:
X = 2( Ra + Rb)
Substituting the values of Ra and Rb Using the first set of equations
X = 2( x/Ta + x/Tb)
But Ta = Tb - 3
1/2 = 1/(Tb - 3)+ 1/Tb
0.5 = (Tb + Tb-3)/Tb(Tb - 3)
At this juncture let’s say Tb = y
0.5 = (2y - 3)/y(y - 3)
y(y-3 ) = 4y - 6
y^2 -3y - 4y + 6 = 0
y^2 -7y + 6= 0
Solving the quadratic equation, we get y =
y = Tb = 6hrs or 1hr
We remove one hour as we know that Tap A takes 3hrs left than tap B and there is nothing like negative hours
Now, we get Ta by Tb -3 = 6 - 3 = 3hrs
Answer:
1184
Step-by-step explanation:
Given :
No. of parts made by machine A in 10 minutes = 7
No. of parts made by machine A in 10*6 minutes (1 hour) = 7 * 6 = 42 parts
No. of parts made by machine A in 12 hours as
required in problem = 42 * 12 = 504
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No. of parts made by machine B in 15 minutes = 17
No. of parts made by machine A in 15*4 =60 minutes (1 hour) = 17 * 4= 68 parts
No. of parts made by machine B in 10 hours as
required in problem = 68 * 10 = 680
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There fore total no. of parts made by
machine A and machine B on Monday = 680 + 504 = 1184 (Answer)
