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3 years ago

Why does tramadol make you fall asleep sitting

1 answer:

3 0

Answer: Tramadol is a narcotic that contains the ingredients tramadol hydrochloride, colloidal silicon dioxide l, hypromellose (sleep inducer), etc.

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I need help with my answer. If you could show your work that would be great.

Paladinen [302]

Answer:

$8 = m$

Step-by-step explanation:

$\frac{-y_1 + y_2}{-x_1 + x_2} = m$

$\frac{0 + 80}{0 + 10} = \frac{80}{10} = 8$

* You are correct my friend!

I am joyous to assist you anytime.

3 0

3 years ago

Which expression represents a factorization of 32m + 56m

luda_lava [24]

Answer:

8m(4+7p)

Step-by-step explanation:

32m = 4*8*m

56 mp = 7*8*m*p

We can factor out an 8m. What is left goes inside the parentheses

32m + 56mp

8m(4+7p)

5 0

4 years ago

2. A snail weighed s ounces. One day the snail drank 5 times its weight in water and ate half its weight in food. Which equation

anastassius [24]

Answer:

Option D : t = 5s + s/2 is the correct answer.

Step-by-step explanation:

Given that:

t = Combined weight of water and food

s = weight of the snail

Water drank by snail = 5s

Food ate by snail = s/2

Combined weight = Weight of water + Food

t = 5s + s/2

Hence,

Option D : t = 5s + s/2 is the correct answer.

4 0

3 years ago

Please help! Will mark brainliest!

Volgvan

Slope=3, Y-intercept=(0,-1)

4 0

3 years ago

A researcher wishes to estimate, with 9090% confidence, the proportion of adults who have high-speed Internet access. Her es

Sunny_sXe [5.5K]

Answer: a) Required minimum sample size= 219

b) Required minimum sample size= 271

Step-by-step explanation:

As per given , we have

Margin of error : E= 5% =0.05

Critical z-value for 90% confidence interval : $z_{\alpha/2}=1.645$

a) Prior estimate of true proportion: p=28%=0.28

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.28(1-0.28)(\dfrac{1.645}{0.05})^2\\\\=218.213856\approx219$

Required minimum sample size= 219

b) If no estimate of true proportion is given , then we assume p= 0.5

Formula to find the sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.645}{0.05})^2\\\\=270.6025\approx271$

Required minimum sample size= 271

8 0

3 years ago