Write equations for the horizontal and vertical lines passing through the point (5, -6)

The perimeter of a triangle is 93 ft. Side a of the triangle is twice as long as side b. Side c is 3 ft longer than side a. Find

Sunny_sXe [5.5K]

The length of side a is 36 feet and side b is 18 feet and side c is 39 feet

Solution:

Given that perimeter of triangle is 93 feet

The three sides of triangle are a, b, and c

Given that Side a of the triangle is twice as long as side b

side a = 2 times side b

a = 2b

$b = \frac{a}{2}$ ---- eqn 1

Given that Side c is 3 ft longer than side a

side c = 3 + side a

c = 3 + a ------ eqn 2

The perimeter of triangle is given as:

p = a + b + c

Where a, b, c are the length of sides of triangle

Substitute eqn 1 and eqn 2 in above formula

$p = a + \frac{a}{2} + 3 + a$

Given that perimeter = 93

$93 = a + \frac{a}{2} + 3 + a\\\\93 = \frac{2a + a + 6 + 2a}{2}\\\\93 \times 2 = 2a + a + 6 + 2a\\\\186 = 5a + 6\\\\5a = 186 - 6\\\\5a = 180\\\\a = 36$

Thus length of side a = 36 feet

Length of side b :

from eqn 1

$b = \frac{36}{2} = 18$

b = 18 feet

Length of side c:

From eqn 2,

c = 3 + 36 = 39

c = 39 feet

Thus length of side a is 36 feet and side b is 18 feet and side c is 39 feet

6 0

4 years ago

Antonio gave 21 tomatoes to his neighbor and 15 to his brother .he had 72 tomatoes before giving some away .how many tomatoes do

Butoxors [25]

He has 36 tomatoes left. Since he had 72 tomatoes in the beginning but gave away 21 to his neighbor and 15 to his brother, you have to subtract those two values from 72. The equation would be 72-21-15 which results in 36. Therefore, Antonio has 36 tomatoes left.

8 0

3 years ago

Read 2 more answers

In parallelogram ABCD , diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E, AE = 3x - 5, and CE = x + 11.

german

Answer:

38

Step-by-step explanation:

For the case of a parallelogram, when the diagonals ( in our case AC & BD) are intersected, they are basically bisected ( divided into two equal halves ). Therefore when the diagonals intersect at point E, we can say that the diagonal AC is divided in two equal halves which in our case are AE and CE. since AE and CE are equal , we can say that,

$AE= CE \\or\\3x-5 = x+11 ---- (1)\\now solving (1) for x, \\3x-x=11+5\\2x=16\\x=8-----> (2)\\\\as \\ AC = AE+CE\\AC = 3x-5+x+11\\AC = 4x+6\\\\\\from (2)\\\\\\AC= 4(8)+6\\AC = 32+6\\AC = 38\\\\since AC = BD ( Diagonals are of same Length )\\therefore \\BD =38$