I looked it up, it says eq triangles have 3 sides. An isos triangle is one with 2 equal sides. Every eq triangle is isos, but not every isos triangle is equilateral. I think the statement in the photo is true.
the answer is true because if you have 3x2 it is the same as 3xx2
Cosine of angle A is also x
This is because the sine is opposite over hypotenuse and cosine is adjacent over hypotenuse so both sine and cosine in this example are asking for the same side over the hypotenuse which means cosine of angle A will be the same as sine of angle B
I believe this is correct but I may be wrong, let me know what it ends up being!
Answer: x = {+-sqrt(3), +-2*sqrt(3)}.
Step-by-step explanation:
(x^2 - 8)^2 + (x^2 - 8) = 20
▪︎ Let (x^2 - 8) be y.
Then,
y^2 + y = 20
y^2 + y - 20 = 0
D = b^2 - 4ac = 1 + 20*4 = 81 = 9^2
y1 = (-b - sqrt(D))/(2a) = (-1 - 9)/2 = -10/2 = -5
y2 = (-b + sqrt(D))/(2a) = (-1 + 9)/2 = 8/2 = 4
1) x^2 - 8 = -5
x^2 = 8 - 5
x^2 = 3
x = +-sqrt(3)
2) x^2 - 8 = 4
x^2 = 8 + 4
x^2 = 12
x = +-sqrt(12)
x = +-2*sqrt(3)
Answer:
no solution
Step-by-step explanation:
