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PSYCHO15rus [73]
3 years ago
10

Basically, if for every row, the absolute value of the entry along the main diagonal is larger than the sum of the absolute valu

es of all other entries on that row. Write a function whose input is a matrix and will determine (true/false) if a matrix is diagonally dominant. Show that your function works as expected.

Computers and Technology
1 answer:
Elza [17]3 years ago
3 0

Answer:

Check the explanation

Explanation:

MATLAB code:

%----------------------

function result = dominant(A)

% matrix dimensions

d = size(A);

% for loop over rows

for i = 1:d

% sum of row elements except diagonal element

sum_row =0;

% for loop over columns

for j = 1:d

% adding each elements to sum variable

sum_row = sum_row+ abs(A(i,j));

end

%subratcting diagonal element

sum_row = sum_row-abs(A(i,i));

%checking dominant condition

% failed once means matrix is not diagonal dominant

if abs(A(i,i))< sum_row

result = 'false';

return;

end

end

% dominant condition not failed

result = 'true';

end

% matrix A

A = [ 3 -2 1; 1 -3 2; 1 2 6]

% result

result = dominant(A)

% matrix A

A = [ -2 1 2; 1 3 2; 1 -2 0]

% result

result = dominant(A)

%----------------------

Kindly check the attached output image below.

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Define an iterative function named append_ordered; it is passed two arguments: a linked list (ll) whose values are ordered from
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Answer:

A python programming language (code) was used for this exercise.

The code is shown below in the explanation section

Explanation:

Solution

Python code:

class LN:

def __init__(self,value,next=None):

self.value = value

self.next = next

  def list_to_ll(self,l):

if l == []:

return None

front = rear = LN(l[0])

for v in l[1:]:

rear.next = LN(v)

rear = rear.next

return front

  def str_ll(self,ll):

answer = ''

while ll != None:

answer += str(ll.value)+'->'

ll = ll.next

return answer + 'None'

def append_ordered(self,ll,v):

ln1=LN(v); #create a node with the new value by creating an instance of the LN class

if ll is None: #if the linked list is empty

ll=ln1 #return the new created node

elif(ll.value >= ln1.value): #if the value to be add is smallest, append the linked list to it

ln1.next=ll

ll=ln1

else:

current=ll; #crate a temporary pointer to iterate over linked list

#iterate till the next node value is smaller than the new value and list is not over

while (current.next is not None and current.next.value < ln1.value):

current=current.next

ln1.next=current.next #save the current node in the next of the new node

current.next=ln1 #save new node in the next of current node

return ll

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answer=ln.str_ll(ll1);    

print(answer); #print the linked list

ll2=ln.append_ordered(ll1,3); #append the value 3 in the linked list

answer=ln.str_ll(ll2)

print(answer); #print the new linked list

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Note: Kindly find the output python code attached to the question below.

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