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Scorpion4ik [409]
3 years ago
6

A new car was put into production. It involved many assembly tasks. Each car was inspected at the end of the assembly line and t

he number of defects per unit was recorded. For the first 100 cars produced, there were 30 defective cars. Some of the cars had no defects; a few had one defect, and so on. The distribution of defects followed a Poisson distribution. Based on the first 100 produced, about how many out of every 1,000 cars assembled should have one or more defects?
Mathematics
1 answer:
allsm [11]3 years ago
5 0

Answer:

About 300 of every 1,000 cars assembled should have one or more defects

Step-by-step explanation:

From the sample of 100 cars, we can estimate the total number of defective cars, using a rule of three.

In this question:

For each 100 cars, 30 defective.

How many defective for 1000?

100 cars - 30 defective

1000 cars - x defective

100x = 30*1000

Simplifying by 100

x = 30*10

x = 300

About 300 of every 1,000 cars assembled should have one or more defects

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True. a homogeneous mixture in which there is a solvent and solute is a solution.
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3 years ago
When it says graph the image, it's asking me to graph a reflection across x = -2. what's the answer look like?
uranmaximum [27]

The reflection across x = -2 will be x = 2.

8 0
3 years ago
Please help me ive been stuck on this question for days! Thank you
Zielflug [23.3K]
Okay, so this is basically telling you that there is no solution. You don't have to worry about there being one. You just have to justify (or explain) why there isn't one.

Basically, neither y or x is equal to anything. You couldn't make x equal to a value in y because x and y are both together in the equation and equal to numbers. 

We can always move a factor to the other side. So,

x-2y= -8

Add 2y to the other side.

x= -8+2y

Now, plug in -8+2y as x.

3(-8+2y)- 6y=-12

-24+6y-6y= -12

The 6y's cancel out. So, we can't figure out what y is.

-24=-12 <- no y.

These two lines are 
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I hope this helps! 
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6 0
4 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

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Serggg [28]

Answer:

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Step-by-step explanation:

Jamarcus is better because he needs 10 more shots to reach 25 while tyrell needs 18 More shots to make 50

8 0
3 years ago
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