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timama [110]
3 years ago
13

The number of miles a car can be driven depends on the number of gallons of gas its tank. The function m = 25g models a situatio

n in which a car gets 25 miles per gallon. If the gas tank holds 20 gallons of gas, which inequality represents its range?
Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0
The correct answer would be, "B. 0 ≤ m ≤ 500".

Hoped I helped!
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I need help what is 30% of 31
Ainat [17]

Answer:

9.3

Step-by-step explanation:

Is means equals and of means multiply

W = 30% * 31

Change to decimal form

W = .30 *31

W = 9.3

4 0
2 years ago
Read 2 more answers
Prove that there exists a unique real number solution to the equation x3 + x2 − 1 = 0 between x = 2/3 and x=1
ziro4ka [17]
Replace each of the x values given to see if they give 0. 

0=(2/3)³+(2/3)²-1 
0=(8/27)+(4/9)-1 
0≠-0.259

0=(1)³+(1)²-1 
0≠1

Therefore, you can see that the solution would have to be between 2/3 and 1.

Hope I helped :) 
7 0
3 years ago
Can someone answer 2,3,4
DENIUS [597]
2: 335 cause you have to do 80b+5s= 80(4)= 320
5(3)=15
320+15=335
8 0
3 years ago
Explain why each non-zero integer has two square roots but only one cube root.
lilavasa [31]

if we have a number like say hmm 4, and we say hmmm √4 is ±2, it simply means, that if we multiply that number twice by itself, we get what's inside the root, we get the 4, so (+2)(+2) = 4, and (-2)(-2) = 4, recall that <u>minus times minus = plus</u>.

so, any when we're referring to even roots like \bf \sqrt[2]{~~},\sqrt[4]{~~},\sqrt[6]{~~}...., the positive number, that can multiply itself an even amount of times, will produce a valid value, BUT the negative number that multiply itself an even amount of times, will also produce a valid value.

now, that's is not true for odd roots like \bf \sqrt[3]{~~},\sqrt[5]{~~},\sqrt[7]{~~}...., because the multiplication of the negative number will not produce a valid value, let's put two examples on that.


\bf \sqrt[3]{27}\implies \sqrt[3]{3^3}\implies 3\qquad because\qquad (3)(3)(3)=27&#10;\\\\\\&#10;however\qquad (-3)(-3)(-3)\ne 27~\hspace{8em}(-3)(-3)(-3)=-27&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\sqrt[3]{-125}\implies \sqrt[3]{-5^3}\implies -5\qquad because\qquad (-5)(-5)(-5)=-125&#10;\\\\\\&#10;however\qquad (5)(5)(5)\ne -125~\hspace{10em}(5)(5)(5)=125


so, when the root is an odd root, you will always get only one number that will produce the radicand.

6 0
3 years ago
I would appreciate some help with this!
olganol [36]
Circumference is
2\pi(r)
so the circumference is
20\pi
5 0
3 years ago
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