If 9x+2y2−3z2=132 and 9y−2y2+3z2=867, then x+y =
1 answer:
Looking at these two equations, you need to cancel out the variables with powers and the z. This can be simply done by adding them. 9y-2y^2+3z^2=867 + 9x+2y^2-3z^2=132 ----------------------------- 9y+9x=999 Factor the 9 out of the left side. 9(x+y)=999 x+y=111 The answer is C (111).
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