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sergey [27]
4 years ago
12

You are in charge of designing a menu tree for navigating 1,250 books in a digital library. Present an argument of whether the m

enu should have larger depth (number of levels) or breadth (number of items per level).
Computers and Technology
1 answer:
Ghella [55]4 years ago
7 0

Answer:

The best way to know whether menu should have a larger depth or breadth is to view the extreme.

Explanation:

The best way to examine menu depth versus breadth is to view the extremes first. Wouldn't it be rather cumbersome to have 1 menu with a long list of 1,250 books on it? How weird would it be to have 1,250 menus each having 1 level deep?Grouping of items naturally to reduce into “smaller sizes” may follow how books are classified now, for instance, Dewey Decimal System, e.g. History books, fiction, non-fiction, dictionaries, etc. Well, remember when you are building a book web site, you may chooseto classify the books in a manner that can increase sales, e.g. Top twenty best sellers, irrespective of their classification, types or for business reasons.

This is easily discussed in the classroom with menu tree diagrams at a white-board to ease editing. This author often emphasizes there is not a perfect correct answer, pointing out that a good and healthy design discussions with user-friendly testing will yield a more preferred solution.

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g 1. Write a program that asks the user for a number greater than 5 and prints all values between 1 and n that are multiples of
a_sh-v [17]

PROGRAM 1

#include <iostream>  

using namespace std;

int main() {

   int n;

   // user input taken for n

   cout<<"Enter any number greater than five: ";

   cin>>n;

   

   cout<<"The multiples of 5 between 1 to "<<n<<" are shown below."<<endl;

   

   // displaying multiples of 5 between 1 to n

   for(int h=1; h<=n; h++)

   {

       // if number is completely divisible by 5, remainder will be 0

       if( (h%5)==0)

           cout<<h<<endl;

   }

 

   return 0;

}

OUTPUT

Enter any number greater than five: 22

The multiples of 5 between 1 to 22 are shown below.

5

10

15

20

The program does not implements any input validation since this is not mentioned in the question.

User input is taken. All the multiples of 5 computed inside a for loop, and displayed to the console.

PROGRAM 2

#include <iostream>

using namespace std;

int main() {

   // variables to hold respective values

   int n;

   int sum=0;

   double avg=0;

   

   do

   {

       // user input taken for n

       cout<<"Enter any number between 1 and 100: ";

       cin>>n;

       if(n<1 || n>100)

           cout<<"Invalid number. Enter valid number."<<endl;

       cout<<""<<endl;

       

   }while(n<1 || n>100);

   

   // computing sum and average of numbers from 1 to n

   for(int h=1; h<=n; h++)

   {

       sum = sum+h;

   }

   

   avg=avg+(sum/n);

   

   cout<<"Sum of all the numbers from 1 to "<<n<<" is "<<sum<<endl;

   

   cout<<""<<endl;

   cout<<"Average of all the numbers from 1 to "<<n<<" is "<<avg<<endl;

   

   return 0;

}

OUTPUT

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Invalid number. Enter valid number.

Enter any number between 1 and 100: 0

Invalid number. Enter valid number.

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Average of all the numbers from 1 to 23 is 12

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The sum of all numbers from 1 to n computed inside a for loop, average computed outside for loop.

Both values are displayed to the console.

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Explanation:

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