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den301095 [7]
3 years ago
12

?? help please!

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
You must get a common denominator of 100. Transfer 594 7/25 to 14857/25 by multiplying 594 by 25. Then multiple 25 and the numerator by 4. For your answer of 59428/100. Then add 59428/100 + 8937/100 for the answer of 68365 then divide it by 100. overall answer should be 683.65. hope this helps
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Identify an equation in point-slope form for the line perpendicular to y =3/4x -4 that passes through (-1, 7).
PilotLPTM [1.2K]

Answer:

y - 7 = -4/3(x + 1)

Step-by-step explanation:

<u>Given</u>

  • y =3/4x -4
  • (-1, 7)

<u>Convert to point slope form</u>

y - y1 = m(x - x1)

m: represents what the slope is

y - 7 = -4/3(x + 1)

<u>Distribute -4/3</u>

-4/3 * x = -4/3x

-4/3 * 1 = -4/3

y - 7 = -4/3x - 4/3

<u>Add seven in both sides</u>

21/3 -4/3 = 17/3

y = -4/3x + 17/2

<u>Answer</u>

linear equation: y = -4/3x + 17/2

point-slope form: y - 7 = -4/3(x + 1)

3 0
3 years ago
Find the lenght of ab
DerKrebs [107]

Answer:

20.6 cm (im pretty sure lol)

Step-by-step explanation:

sine rule:

(ab = x)

13.5/sin41 = x/sin90

13.5sin90/sin41 = x

x = 20.57741667

ab = 20.6cm

7 0
3 years ago
How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
Draw two different perimeters of a rectangle with an area of 14 units. Name their dimensions.
Alenkasestr [34]
1:
Length: 7
Width:2
Perimeter: 18

2:
Length: 5
Width: 2.8
Perimeter: 15.6
8 0
3 years ago
Find the value of x and y in the parallelogram below.
sashaice [31]

Answer:

x = 18°

y = 6

Step-by-step explanation:

in a parallelogram:

Any two opposite sides are congruent

and any two opposites angles are congruent:

then

y + 4 = 10

and 3x = 54

then

y = 6

and x =  54/3 = 18

8 0
2 years ago
Read 2 more answers
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