Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:

Re-write 'em as a standard form:

So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:

And they do not have any collision point
Answer:
Yes. No graph paper.
Step-by-step explanation:
Let's say the 3 points are A, B, C.
If A, B and C lie on one line then 

Hence, they lie on one line.
You don't need to use a graph paper to prove it.
Answer:
LINE D
Step-by-step explanation:
Answer:
answer of this question is
35.24
Answer:
8/25
Step-by-step explanation:
So 32% is essentially 32/100 now we can divide that even more so now we have 16/50(we divided it in half) but we can divide that again, so now we have 8/25 :)